Of course a segment tree problem.
Let's start from $f$. Then actually, the state of last day is fixed. Also fixed for the day before last day. The only thing we need to know is how many zeros between $l$ to $r$. Then we can know what is changed.
For example the next state between $l$ and $r$ is $00011$. Then it must be changed from $00000$. Then change it back. And see if it match $s$.